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Acres altitude angle applied axes axis base body Book breadth called cask centre chord circle circular circumference common computed cone constructed contain cosine cubic curve cylinder decimals describe diagonal diagram diameter difference distance divided draw drawn ellipse employed equal EXAMPLES expression extremities faces feet feet 6 inches figure fixed follows foot four frustum gallons geometry give given greater half head height Hence hypotenuse imperial inches learner length less logarithm mean measures method middle multiplying namely opposite parabola parallel parallelogram perpendicular plane polygon portion practical present prism PROBLEM pyramid radius reference regular Required the area Required the solid result right-angled ring rule segment sides similar sine slant solid content sphere spheroid square straight line subtract supposed surface taken thickness third triangle unit vertex whole yards zone
Page 28 - Pythagoras' theorem states that the square of the length of the hypotenuse of a right-angled triangle is equal to the sum of the squares of the lengths of the other two sides.
Page 85 - From eight times the chord of half the arc, subtract the chord of the whole arc, and divide the remainder by 3, and the quotient will be the length of the arc, nearly.
Page 151 - From three times the diameter of the sphere subtract twice the height of the segment; multiply this remainder by the square of the height and the product by 0.5236.
Page 139 - Pyramid. RULE. — Multiply the sum of the perimeters of the two ends by the slant height or side of the frustum, and half the product will be the surface required.
Page 222 - Add into one sum 39 times the square of the bung diameter, 25 times the square of the head diameter, and 26 times the product of the...
Page 31 - Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area.
Page 17 - To measure a Parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area or superficial content.
Page 55 - Ans. 23° 3' 55". 4. From the edge of a ditch 18 feet wide, surrounding a fort, I took the angle of elevation of the top of the wall and found it 62° 40...
Page 86 - Multiply half the circumference by half the diameter, and the product will be the area. Or, divide the product of the whole circumference and diameter -by 4, and the quotient will be the area. 2. Multiply the square of the diameter by .7854, and the product will be the area.