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" KCML, the sum of the two parallelograms or square BCMH ; therefore the sum of the squares on AB and AC is equal to the square on BC. "
A Compleat Treatise of Practical Navigation Demonstrated from It's First ... - Page 22
de Archibald Patoun - 1734 - 414 pages
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A Treatise of Practical Surveying: Which is Demonstrated from Its First ...

Robert Gibson - 1795 - 319 pages
...Sum of the Squares, Plate I. Squares, = BKLH+KCML, the Sum of the two Parallelograms or Square BCMH ; therefore the Sum of the Squares on AB and AC is equal to the Square on BC. Q^ ED Cor. i. Hence the Hypothenufe of a rightangled Triangle may be found by having the Legs ; thus,...
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A Treatise of Practical Surveying: Which is Demonstrated from Its First ...

Robert Gibson - 1806 - 452 pages
...ACGF the sum of the Plate I. squares = BELH + KCML, the sum of the two parallelograms or square BCMH ; therefore the sum of the squares on AB and AC is equal to the square on BC. QED Cor. Hence the hypothenuse of a right-angled triangle may be found by having the legs ; thus, the...
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A Treatise of Practical Surveying, ...

Robert Gibson - 1808 - 440 pages
...ACGF the sum of the Plate I. squares, = BKLH+KCML, the sum of the two parallelograms or square BCMH ; therefore the sum of the squares on AB and AC is equal to the square on BC. -QED Cor. 1. Hence the hypothenuse of a rightangled triangle may be found by having the legs ; thus,...
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The Theory and Practice of Surveying: Containing All the Instructions ...

Robert Gibson - 1811 - 508 pages
...So AB DE + ACGF the sum of the &quvces=BKLH+KCML, the sum of the two parallelograms or square BCMH ; therefore the sum of the squares on AB and AC is equal to the square on BC. 2. ED Cor. 1. Hence the hypothenuse of a right-angled triangle may Its found by having the sides ;...
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The Theory and Practice of Surveying: Containing All the Instructions ...

Robert Gibson - 1814 - 508 pages
...ABDE+ACGFûie sum of the squares= BKLH + KCML, the sum of the two parallelograms or square BCMH ; thei'efore the sum of the squares on AB and AC is equal to tiie square on BC. QED Cor. 1. Hence the hypothenuse of a right-angled triangle may be found by having...
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The New American Practical Navigator: Being an Epitome of Navigation ...

Nathaniel Bowditch - 1826 - 617 pages
...parallelograms BKLH and KCML : the sum of these parallelograms is equal to the square BCMH, therefore sum of the squares on AB and AC is equal to the square on BC. Cor. Hence in any right angled triangle, if we have the hypotenuse one of the legs, we may easily find the...
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The New American Practical Navigator: Being an Epitome of Navigation ...

Nathaniel Bowditch - 1826 - 617 pages
...BKLH and KCML ; but lhe. sum of these parallelograms is equal to the square BCMH, therefore the iyirn of the squares on AB and AC is equal to the square on BC. Cor. Hence in any right angled triangle, if we have the hypotenuse and one of the legs, we may easily find...
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The Theory and Practice of Surveying: Containing All the Instructions ...

Robert Gibson - 1832 - 348 pages
...ABDE+ACGF the sum of the squares —BKLH-\-KCML, the sum of the two parallelograms or square BCMH; therefore the sum of the squares on AB and AC is equal to the square on BC. QED* . Cor. 1. Hence the hypothenuse of a right-angled triangle may be found by having the sides :...
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The Theory and Practice of Surveying: Containing All the Instructions ...

Robert Gibson, James Ryan - 1839 - 412 pages
...the squares =BKLH+KCML, the sum of the two parallelograms or square BCMH; therefore the sum of ihe squares on AB and AC is equal to the square on BC. QED* Cor. 1. Hence the hypothenuso of a right-angled triangle may be found by having the sides i thus,...
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The New American Practical Navigator; Being an Epitome of Navigation ...

Nathaniel Bowditch - 1846 - 451 pages
...JMrallelograms BKLH and KCML; but the sum of these parallelograms is equal to the square ВСЛ1Н ; therefore the sum of the squares on AB and AC is equal to the square on BC. Cor. Hence, in any right-angled triangle, if we have the hypotenuse and one of the legs, we may easily find...
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