Exercises in Classical Ring TheorySpringer Science & Business Media, 9 mai 2006 - 364 pages This useful book, which grew out of the author's lectures at Berkeley, presents some 400 exercises of varying degrees of difficulty in classical ring theory, together with complete solutions, background information, historical commentary, bibliographic details, and indications of possible improvements or generalizations. The book should be especially helpful to graduate students as a model of the problem-solving process and an illustration of the applications of different theorems in ring theory. The author also discusses "the folklore of the subject: the `tricks of the trade' in ring theory, which are well known to the experts in the field but may not be familiar to others, and for which there is usually no good reference". The problems are from the following areas: the Wedderburn-Artin theory of semisimple rings, the Jacobson radical, representation theory of groups and algebras, (semi)prime rings, (semi)primitive rings, division rings, ordered rings, (semi)local rings, the theory of idempotents, and (semi)perfect rings. Problems in the areas of module theory, category theory, and rings of quotients are not included, since they will appear in a later book. T. W. Hungerford, Mathematical Reviews |
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Résultats 1-5 sur 17
Page 1
... Dedekind-finiteness. A ring R is said to be Dedekind-finite if ab = 1 in R implies that ba = 1. The chain conditions are the usual noetherian (ACC) or artinian (DCC) conditions which can be imposed on submodules of a module, or on 1 ...
... Dedekind-finiteness. A ring R is said to be Dedekind-finite if ab = 1 in R implies that ba = 1. The chain conditions are the usual noetherian (ACC) or artinian (DCC) conditions which can be imposed on submodules of a module, or on 1 ...
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... Dedekind-finite. Solution. The statement in quotes is false in general. If R is a ring that is not Dedekind-finite, then, for suitable a, b ∈ R, we have ab = 1 = ba. Here, ab is a unit, but neither a nor b is a unit. (Conversely, it is ...
... Dedekind-finite. Solution. The statement in quotes is false in general. If R is a ring that is not Dedekind-finite, then, for suitable a, b ∈ R, we have ab = 1 = ba. Here, ab is a unit, but neither a nor b is a unit. (Conversely, it is ...
Page 3
... Dedekindfinite ring, say with xy = 1 = yx. Then xR contains 1 so xR = R, but 1 ∈ Rx implies that Rx ⊊ R = xR. nonzero ring k, and let x = Ex. 1.6. Let a, b be elements in a ring R. If 1 − ba is left-invertible (resp. invertible) ...
... Dedekindfinite ring, say with xy = 1 = yx. Then xR contains 1 so xR = R, but 1 ∈ Rx implies that Rx ⊊ R = xR. nonzero ring k, and let x = Ex. 1.6. Let a, b be elements in a ring R. If 1 − ba is left-invertible (resp. invertible) ...
Page 7
... Dedekindfinite.3 (3) Deduce from (1), (2) that any left noetherian ring R is Dedekind-finite. Solution. (1) Let α : M → M be surjective and M be noetherian. The ascending chain kerα ⊆ kerα2 ⊆··· must stop, so ker αi = kerαi+1 for ...
... Dedekindfinite.3 (3) Deduce from (1), (2) that any left noetherian ring R is Dedekind-finite. Solution. (1) Let α : M → M be surjective and M be noetherian. The ascending chain kerα ⊆ kerα2 ⊆··· must stop, so ker αi = kerαi+1 for ...
Page 8
... Dedekind-finite. (b) Show that a left 0-divisor of A is also a right 0-divisor. (c) Show that a nonzero element of A is a unit iff it is not a 0-divisor. (d) Let B be a subalgebra of A, and b∈ B. Show that b is a unit in B iff it is a ...
... Dedekind-finite. (b) Show that a left 0-divisor of A is also a right 0-divisor. (c) Show that a nonzero element of A is a unit iff it is not a 0-divisor. (d) Let B be a subalgebra of A, and b∈ B. Show that b is a unit in B iff it is a ...
Table des matières
Jacobson Radical Theory | 49 |
Introduction to Representation Theory | 99 |
Ordered Structures in Rings 247 | 246 |
Perfect and Semiperfect Rings 325 | 324 |
Name Index | 349 |
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Expressions et termes fréquents
0-divisor 2-primal abelian algebra artinian ring assume automorphism commutative ring conjugate constructed contradiction cyclic Dedekind-finite defined direct product direct summand division ring domain element endomorphism equation Exercise exists fact field finite group finite-dimensional follows group G hence homomorphism hopfian idempotent identity implies indecomposable induction infinite integer inverse irreducible isomorphism J-semisimple Jacobson radical k-algebra kG-module left ideal left primitive Lemma Let G local ring Math maximal ideal maximal left ideal Mn(k Mn(R module multiplication Neumann regular ring nil ideal Nilº noetherian ring noncommutative nonzero polynomial prime ideal primitive rings proof prove R-module R/rad rad kG representation resp right ideal right R-module ring theory semilocal ring semiprime semisimple ring show that rad simple ring Solution stable range subdirect product subgroup submodule subring suffices to show surjective Theorem unit-regular von Neumann regular zero