Exercises in Classical Ring TheoryThis useful book, which grew out of the author's lectures at Berkeley, presents some 400 exercises of varying degrees of difficulty in classical ring theory, together with complete solutions, background information, historical commentary, bibliographic details, and indications of possible improvements or generalizations. The book should be especially helpful to graduate students as a model of the problem-solving process and an illustration of the applications of different theorems in ring theory. The author also discusses "the folklore of the subject: the `tricks of the trade' in ring theory, which are well known to the experts in the field but may not be familiar to others, and for which there is usually no good reference". The problems are from the following areas: the Wedderburn-Artin theory of semisimple rings, the Jacobson radical, representation theory of groups and algebras, (semi)prime rings, (semi)primitive rings, division rings, ordered rings, (semi)local rings, the theory of idempotents, and (semi)perfect rings. Problems in the areas of module theory, category theory, and rings of quotients are not included, since they will appear in a later book. T. W. Hungerford, Mathematical Reviews |
À l'intérieur du livre
Résultats 1-5 sur 88
Page 2
Solution. Suppose the domain R has characteristic n =0. If n is not a prime, then n = n1n2 where 1 < ni < n. But then ni1 =0, and (n11)(n21) = n1 = 0 contradicts the fact that R is a domain. Ex. 1.4.
Solution. Suppose the domain R has characteristic n =0. If n is not a prime, then n = n1n2 where 1 < ni < n. But then ni1 =0, and (n11)(n21) = n1 = 0 contradicts the fact that R is a domain. Ex. 1.4.
Page 6
(b) For any nonzero ring k, R = {( a b 0 0 ) : a,b∈k } is a right ideal of M2(k). Therefore, (R, +, ×) satisfies all the axioms of a ring, except perhaps the identity axiom. An easy verification shows that R has in fact no identity.
(b) For any nonzero ring k, R = {( a b 0 0 ) : a,b∈k } is a right ideal of M2(k). Therefore, (R, +, ×) satisfies all the axioms of a ring, except perhaps the identity axiom. An easy verification shows that R has in fact no identity.
Page 7
In fact, an endomorphism α : R R → R R is given by right multiplication by b = α(1), and αi is given by right multiplication by bi. Thus, ker (αi) = annl(bi) and we need only assume that any left annihilator chain annl(b) ⊆ annl(b2) ...
In fact, an endomorphism α : R R → R R is given by right multiplication by b = α(1), and αi is given by right multiplication by bi. Thus, ker (αi) = annl(bi) and we need only assume that any left annihilator chain annl(b) ⊆ annl(b2) ...
Page 11
For any a e K, we have ha e I = R h, so ha = rh for some re R. By comparing the leading terms, we see that r e K, and in fact r = a. Thus, ha = ah for any a e K, which means that he k|a|. Ex. 1.17. Let ac, y be elements in a ring R such ...
For any a e K, we have ha e I = R h, so ha = rh for some re R. By comparing the leading terms, we see that r e K, and in fact r = a. Thus, ha = ah for any a e K, which means that he k|a|. Ex. 1.17. Let ac, y be elements in a ring R such ...
Page 12
(The fact that R ∼= S is a special case of Exercise 1.22(1) below.) Ex. 1.19. Let R be a domain. If R has a minimal left ideal, show that R is a division ring. (In particular, a left artinian domain must be a division ring.) Solution.
(The fact that R ∼= S is a special case of Exercise 1.22(1) below.) Ex. 1.19. Let R be a domain. If R has a minimal left ideal, show that R is a division ring. (In particular, a left artinian domain must be a division ring.) Solution.
Avis des internautes - Rédiger un commentaire
Aucun commentaire n'a été trouvé aux emplacements habituels.
Table des matières
Jacobson Radical Theory | 49 |
Introduction to Representation Theory | 99 |
Ordered Structures in Rings 247 | 246 |
Perfect and Semiperfect Rings 325 | 324 |
Name Index | 349 |
Autres éditions - Tout afficher
Expressions et termes fréquents
0-divisor 2-primal abelian algebra artinian ring assume automorphism commutative ring conjugate constructed contradiction cyclic Dedekind-finite defined direct product direct summand division ring domain element endomorphism equation Exercise exists fact field finite group finite-dimensional follows group G hence homomorphism hopfian idempotent identity implies indecomposable induction infinite integer inverse irreducible isomorphism J-semisimple Jacobson radical k-algebra kG-module left ideal left primitive Lemma Let G local ring Math maximal ideal maximal left ideal Mn(k Mn(R module multiplication Neumann regular ring nil ideal Nilº noetherian ring noncommutative nonzero polynomial prime ideal primitive rings proof prove R-module R/rad rad kG representation resp right ideal right R-module ring theory semilocal ring semiprime semisimple ring show that rad simple ring Solution stable range subdirect product subgroup submodule subring suffices to show surjective Theorem unit-regular von Neumann regular zero
Informations bibliographiques
| Titre | Exercises in Classical Ring Theory Problem Books in Mathematics |
| Auteur | T.Y. Lam |
| Édition | 2, illustrée |
| Éditeur | Springer Science & Business Media, 2006 |
| ISBN | 0387217711, 9780387217710 |
| Longueur | 364 pages |
| Exporter la citation | BiBTeX EndNote RefMan |