Exercises in Classical Ring TheorySpringer Science & Business Media, 9 mai 2006 - 364 pages This useful book, which grew out of the author's lectures at Berkeley, presents some 400 exercises of varying degrees of difficulty in classical ring theory, together with complete solutions, background information, historical commentary, bibliographic details, and indications of possible improvements or generalizations. The book should be especially helpful to graduate students as a model of the problem-solving process and an illustration of the applications of different theorems in ring theory. The author also discusses "the folklore of the subject: the `tricks of the trade' in ring theory, which are well known to the experts in the field but may not be familiar to others, and for which there is usually no good reference". The problems are from the following areas: the Wedderburn-Artin theory of semisimple rings, the Jacobson radical, representation theory of groups and algebras, (semi)prime rings, (semi)primitive rings, division rings, ordered rings, (semi)local rings, the theory of idempotents, and (semi)perfect rings. Problems in the areas of module theory, category theory, and rings of quotients are not included, since they will appear in a later book. T. W. Hungerford, Mathematical Reviews |
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Résultats 1-5 sur 80
Page 3
... follows immediately from (b). Ex. 1.4*. Let a ∈ R, where R is any ring. (1) Show that if a has a left inverse, then a is not a left 0-divisor. (2) Show that the converse holds if a ∈ aRa. Solution. (1) Say ba = 1. Then ac = 0 implies ...
... follows immediately from (b). Ex. 1.4*. Let a ∈ R, where R is any ring. (1) Show that if a has a left inverse, then a is not a left 0-divisor. (2) Show that the converse holds if a ∈ aRa. Solution. (1) Say ba = 1. Then ac = 0 implies ...
Page 4
... follows that each ei is central. We finish easily 2 This trick was also mentioned in an article of P.R. Halmos in Math. Intelligencer 3 (1981), 147–153. Halmos attributed the trick to N. Jacobson. by showing that B1 ×···× Bn → R ...
... follows that each ei is central. We finish easily 2 This trick was also mentioned in an article of P.R. Halmos in Math. Intelligencer 3 (1981), 147–153. Halmos attributed the trick to N. Jacobson. by showing that B1 ×···× Bn → R ...
Page 10
... follows that o is an isomorphism. (Note that o here is not a homomorphism of left C-vector spaces, since o is not the identity map from C C A to C C M2(C)") Ex. 1.16. Let K be a division ring with center k. (1) Show that the center of ...
... follows that o is an isomorphism. (Note that o here is not a homomorphism of left C-vector spaces, since o is not the identity map from C C A to C C M2(C)") Ex. 1.16. Let K be a division ring with center k. (1) Show that the center of ...
Page 15
... follows that annr (N) = . On the other hand, from B Z2 0 Z2 have |annr (N)| = 4, and |annl (N)|= 8. Since the nilpotent elements of R correspond to those of Rop (under the one-one correspondence a ↔ aop), this surely implies that R ...
... follows that annr (N) = . On the other hand, from B Z2 0 Z2 have |annr (N)| = 4, and |annl (N)|= 8. Since the nilpotent elements of R correspond to those of Rop (under the one-one correspondence a ↔ aop), this surely implies that R ...
Page 21
... follows, therefore, that R/A ∼= R/A as R-modules iff there exists an element r ∈ I such that rR + A = R, and rx ∈ A =⇒ x ∈ A. The situation becomes a lot simpler if A, A are replaced by the maximal right ideals m and m. Since R/m ...
... follows, therefore, that R/A ∼= R/A as R-modules iff there exists an element r ∈ I such that rR + A = R, and rx ∈ A =⇒ x ∈ A. The situation becomes a lot simpler if A, A are replaced by the maximal right ideals m and m. Since R/m ...
Table des matières
Jacobson Radical Theory | 49 |
Introduction to Representation Theory | 99 |
Ordered Structures in Rings 247 | 246 |
Perfect and Semiperfect Rings 325 | 324 |
Name Index | 349 |
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Expressions et termes fréquents
0-divisor 2-primal abelian algebra artinian ring assume automorphism commutative ring conjugate constructed contradiction cyclic Dedekind-finite defined direct product direct summand division ring domain element endomorphism equation Exercise exists fact field finite group finite-dimensional follows group G hence homomorphism hopfian idempotent identity implies indecomposable induction infinite integer inverse irreducible isomorphism J-semisimple Jacobson radical k-algebra kG-module left ideal left primitive Lemma Let G local ring Math maximal ideal maximal left ideal Mn(k Mn(R module multiplication Neumann regular ring nil ideal Nilº noetherian ring noncommutative nonzero polynomial prime ideal primitive rings proof prove R-module R/rad rad kG representation resp right ideal right R-module ring theory semilocal ring semiprime semisimple ring show that rad simple ring Solution stable range subdirect product subgroup submodule subring suffices to show surjective Theorem unit-regular von Neumann regular zero