 | Henry Sherwin - 1706 - 430 pages
...Segment of the fide where the Perpendicular fells. Now the fécond Aich comprehended between the fame Segment and the other Angle, is to be found thus:...given Angle adjacent unto the given fide, and from the Sura fubtraâ the Tangent of the other given Angle, the Remainder flull be the Sine of the fécond... | |
 | Henry Sherwin - 1726 - 508 pages
...Segment of the fide where the Perpendicular falls : Now the fécond aren comprehended between the fame Segment and the other angle, is to be found thus : Add the fine of the arch found, to the Tangent of the given angle adjacent unto the given fide, and from the... | |
 | Henry Sherwin - 1772 - 454 pages
...the Segment of the Side where the Perpendicular falls. The fécond Arc comprehended between the fame Segment and the other Angle, is to be found thus : Add the Sine of the Arc found, to the Tangent of the given Angle next the given Side, and from the Sum lubtraft the Tangent... | |
 | Charles Hutton - 1811 - 574 pages
...the side PS. 9-8080675 9-8838294") 850) 0-2808858 ? And the second arc, comprehended between the same segment and the other angle, is to be found thus: add the sine of the arc found, to the tangent of the given angle next the given side, and from the sum subtract the tangent... | |
 | Charles Hutton - 1834 - 466 pages
...segment of the side where the perpendicular falls. And the second arc, comprehended between the same segment and the other angle, is to be found thus : add the sine of the arc found to the tangent of the given angle next the given side, and from the sum subtract the tangvnt... | |
 | Charles Hutton - 1842 - 450 pages
...segment of the side where the perpendicular falls. And the second arc, comprehended between the same segment and the other angle, is to be found thus : add the sine of the arc found to the tangent of the given angle next (he given side, and from the sum subtract the tangent... | |
 | Charles Hutton - 1855 - 462 pages
...segment of the side where the perpendicular falls. And the second arc, comprehended between the same segment and the other angle, is to be found thus : add the sine of the arc found to the tangent of the given angle next the given side, and from the sum subtract the tangent... | |
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And the second arc, comprehended between the same segment and the other angle, is to be found thus : add the sine of the arc found to the tangent of the given angle next... 